dj023102 said:Hi guys, i have attached my question. really am stuck with this one. apparently it is a famous integral from poisson. Any ideas on where to start would be good. Cheers
dj023102 said:The question ask what is the area of a finite cylinder of radius r when it intersect the bell when the function z=e^(-x^2) is rotated around the z axis (to make the bell).
The area is A = pi times (f(x))^2
Is that what the question is asking i think, but is f(x) = e^(-x^2) or because it is rotated around the z axis i need to make x the subject so f(z) = square root of -In(z)
Does it really matter?
splatter said:hey I've been watching this thread for a while, and I am pretty sure i have exactly the same assignment.. anyway the one i have is broken up into 6 sections, the 4th of which is really bugging me. It says "express the area of intersection of the bell (the rotated integral) with the plane parallel to, and a distance y, from the xz-plane as a function S(y).
just stuck on how you would put this intersection into writing, or where to start from. any ideas?
dj023102 said:z = e^(-x^2) on the xz-plane. Then rotate this graph around the z-axis to get a bell shaped infinite surface hovering above the xy-plane. The solid chunk is in a space between the xy-plane and the shape looks like a bell.
When you intersect the bell with the infinite hollow cylinder of radius r and the z-axis as its central axis you get a finite hollow cylinder. How do you find the area of this finite hollow cylinder (this cylinder is lacking the caps on both ends, so the area of these caps don’t occur towards the area of the cylinder)
I have no idea where to start, I always thought a cylinder only has volume. …
dj023102 said:cos after that i need to calculate the volume of the cylinder by integrating the area with lower bound 0 and upper bound infinity.
splatter said:… the reason I am confused is that i end up with [integral e^(-x^2)dx over all x]*[integral e^(-y^2)dy over all y], which presents the same problem as the initial integral of I=int e^(-x^2) dx over all x...
dj023102 said:ah ok! i think i get it. Sorry been looking at the wrong part of the text.
So area of cylinder = (exp(-r^2))*(2*r*pi).
Is that right?
tiny-tim said:hmm … you might have said that at the beginning, so that we knew what the context was.
tiny-tim said:Hint: ∫∫e-x² e-y² dx dy = ∫∫e-r² dx dy …
now change the variables of integration from x and y to r and θ.![]()
splatter said:sorry i just realized i don't understand what you meant by changing the variable y to θ - i don't have any variables except x, y, r, and possibly z.. sorry to be so annoying =/
His_Dudeness3 said:Asking for the volume of the bell, i.e. the integral of C(r)dr with the upper limit being positive infinity and the lower limit being zero, I got: V= -pi*([exp]^(+infinity)-1)
His_Dudeness3 said:I'm looking very hard and I don't know what mistake I've done.
tiny-tim said:Hi His_Dudeness3! Welcome to PF!
(have a pi: π and an infinity: ∞ and an integral: ∫)
erm … let's just start with this:
Do you mean V = -π(e+∞ - 1)?
that's ∞ (which is wrong).
Look at it again … I think you'll find you got a minus in the wrong place.![]()
His_Dudeness3 said:ohh sorry, lol do you mean its supposed to read as follows:
V= -pi*( [exp]^(-∞) -1)
His_Dudeness3 said:2. The next question asks, show that the top of the bell is the graph of the function:
z=[exp]^(-(x^2 + y^2))
I thought I could get this by getting the derivative of V, and finding the top of the bell (i.e. the maximum) by making dV/dr = 0 but I ended up getting -r^(2) = log(o)/log([exp])
Anyone got any thoughts? Am I on the right track?