Tesla Coil Surprises Inside a Faraday Cage

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Inside a Faraday cage, a person can safely touch the interior while exposed to high voltage from a Tesla coil because the electric charge distributes itself on the outer surface, preventing electric fields from penetrating the interior. This phenomenon occurs as electrons repel each other, moving to the edges of the conductor to maximize distance from one another. In electrostatics, the electric field inside a conductor is zero, as charges rearrange to counteract external fields. However, in a copper wire within a circuit, free electrons can flow through the interior, unlike in an isolated conductor. This discussion highlights the principles of electrostatics and charge distribution in conductors.
cragar
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When this guy gets inside the Faraday cage and they hit it with like 200,000 volts from a Tesla coil , when he is inside the cage he can touch the inside and not get shocked , so basically the charge flows on the outside , is this because the electric field from all around the circle pushes the charge to the outside .?

 
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I haven't heard many people talk about electric fields pushing!
A reasonable explanation coming from a slightly different direction is that electrons "don't like one another".
In their efforts to get as far away from one another as convenient, electrons on the inside of a conductive body get out onto the edges and even jump off into the atmosphere.

You might like the information on this link: http://www.howstuffworks.com/vdg.htm
 
thanks for the answer .
 
does the charge on a copper wire only flow on the outside of the wire ,
 
In electrostatics, the field inside a conductor is zero. By electrostatics, I mean an isolated conductor. If it is placed in an external field, the free electrons in the conductor would be acted upon by the field and would more towards the surface closer to the positive end, leaving behind positive atoms (or I should say ions). This separation of charges produces a field that opposes the external field. The separation takes place until the two fields cancel each other out. At this point the electron would be pulled by the the positive ions with the same force as the external force is pulling it in the opposite direction.

A copper wire, it is not an isolated conductor. It is in a circuit. The free electrons would be pulled out of the wire by the current source. As in the previous case they are not forced to settle onto the surface of an isolated conductor. So in a copper wire, electrons flow in the interior region as well.
 
ok thanks for the answer .
 
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...

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