Faraday's Law Problem: Calculating Induced EMF in a Loop of Wire

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The discussion revolves around calculating the induced electromotive force (emf) in a loop of wire as the magnetic field decreases. The initial confusion stemmed from incorrectly using the angle in the flux calculation, where the correct angle is 0 degrees, not 90 degrees. After correcting the area calculation using the radius in meters instead of centimeters, the participants clarified the induced emf should indeed be around 0.0027V. The conversation highlighted the importance of unit conversion and careful geometry in physics problems. Ultimately, the participants expressed a mix of frustration and learning from the experience.
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Homework Statement



Take a loop of wire with a radius of 2.0 cm. A B field is perpendicular to the area enclosed by the wire. If the field is reduced to zero from 0.55 T in 0.25 s, what is the induced emf between the ends of the wire?



Homework Equations


B=Magnetic Field
A=Area
Flux= BA cos(Theta)
EMF = Change in Flux/ Change in time

The Attempt at a Solution



Trying to find Flux but since its perpendicular to the area, cos90 = 0 and this makes no sense. The answer is suppose to be 0.0028V. Any help would be great, Thanks
 
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Your geometry is wrong. You're using the wrong angle.
 
ok my bad its suppose to be cos0 which is 1
with that i found Flux to be = (0.55T)(4pi) which is around 6.9T/m^2
With that 6.9(T/m^2)/0.25(Secs)= 27.6 Volts?
Like i said answer is suppose to be 0.0027V. Is there something wrong or did i just screw up the units some where?
Thanks again...
 
Again the issue is geometry. Look carefully as how you're calculating the area.
 
The area is just( pi)r^2 right?
 
Yes, but be careful what you use for "r".
 
Ohh. I see. its in cm. that should change things abit...Thanks everyone.
 
Success! I have to ask this question: What about physics did you learn from doing this problem?
 
... wat did i learn? I hate physics Tests. =D and UNITS.
 
  • #10
Your answer is more or less correct. My point is that there wasn't much physics in this problem.
 
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