Fel & Fg Interaction: Electron Count for Balance

  • Thread starter Thread starter Praestrigiator
  • Start date Start date
  • Tags Tags
    Interaction
AI Thread Summary
The discussion focuses on the interaction between electrostatic force (Fel) and gravitational force (Fg) in hypothetical objects composed of protons and electrons. Calculations reveal that Fel between two protons at 1 mm is significantly stronger than Fg, indicating that gravity is negligible in atomic structures. The conversation highlights the challenge of balancing the repulsive force of Fel with the attractive force of gravity, particularly when considering the replacement of protons with electrons. It is emphasized that atomic stability relies on electromagnetic and nuclear forces rather than gravity. Ultimately, the relationship between the number of protons and electrons is complex, leading to a mathematical expression that cannot be solved directly without additional information.
Praestrigiator
Messages
27
Reaction score
2
I did the math and figured that Fel between two protons at 1 mm is 2.307E-22 N, and the Fg at the same distance is 1.867E-36 obviously these values change with the number of protons, and distance. this is an issue because I'm trying to imagine a hypothetical object as charged as possible while still held together by gravity. Assuming uniform distribution of protons and electrons, how many electrons are needed to make The repulsive force of Fel less than the attractive force of gravity on an object primarily comprised of protons? What about an object comprised of electrons?
 
Physics news on Phys.org
The biggest problem i see is that in replacing protons with electrons reduces both repulsive Fel and attractive Fg
 
Praestrigiator said:
The biggest problem i see is that in replacing protons with electrons reduces both repulsive Fel and attractive Fg

Atoms and molecules aren't held together by gravity. The force exists, of course, but is negligible compared to the other forces present. They are held together by the electromagnetic force at one level, and the nuclear force (extremely important) at another. Gravity is too weak to be considered here, don't you think? Protons are held together in nuclei not because "surrounding electrons reduce the repulsion between them causing gravity to become more prominent", but because of the strong nuclear force which binds the nucleons together. It is much stronger than the repulsive force between protons.
 
Last edited:
Praestrigiator said:
I did the math and figured that Fel between two protons at 1 mm is 2.307E-22 N, and the Fg at the same distance is 1.867E-36 obviously these values change with the number of protons, and distance. this is an issue because I'm trying to imagine a hypothetical object as charged as possible while still held together by gravity. Assuming uniform distribution of protons and electrons, how many electrons are needed to make The repulsive force of Fel less than the attractive force of gravity on an object primarily comprised of protons?
Let nP be the number of protons and nE be the number of electrons. Write down an expression for the gravitational force from nP+nE, and an expression for the electrostatic force. Set them equal.

You now have one equation in two unknowns, so you cannot solve. But you can solve for nE/nP
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top