For two identical particles, we have(adsbygoogle = window.adsbygoogle || []).push({});

[itex]|\psi(x_1,x_2,t)|^2=|\psi(x_2,x_1,t)|^2[/itex]

thus [itex]\psi(x_1,x_2,t)=e^{i\phi}\psi(x_2,x_1,t)[/itex]

also [itex]\psi(x_2,x_1,t)=e^{i\phi}\psi(x_1,x_2,t)[/itex]

that means [itex]e^{2i\phi}=1[/itex] or [itex]e^{i\phi}=\pm 1[/itex]

For fermions

[itex]\psi(x_2,x_1,t)=-\psi(x_1,x_2,t)[/itex]

Why does it happen to be different when we just switch the position of these particles?

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Fermion-Boson question

Loading...

**Physics Forums - The Fusion of Science and Community**