Few questions about behaviors of a function

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SUMMARY

The discussion focuses on analyzing the function f(x) = ln(1 - lnx) to determine its vertical and horizontal asymptotes, intervals of increase or decrease, and local maximum and minimum values. The derivative of the function is given as f'(x) = 1/(x - xlnx). Participants emphasize the importance of identifying where f'(x) is greater than or less than zero to ascertain the intervals of increase and decrease, as well as solving f'(x) = 0 to find critical points for local extrema.

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Homework Statement


Find the
A) Vertical and horizontal asymptotes
B) *Intervals of increase or decrease*
C) Local max and local min values

For the function:
f(x)= ln(1-lnx)



Homework Equations


I know that the derivative of the function is
f'(x)= 1/(x-xlnx)

but I'm so confused on how to find the asymptotes and the intervals of increase and decrease...



The Attempt at a Solution


Found f'(x) and equated it to zero... but i messed up somewhere.. clueless :S
 
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Sinister said:

Homework Statement


Find the
A) Vertical and horizontal asymptotes
B) *Intervals of increase or decrease*
C) Local max and local min values

For the function:
f(x)= ln(1-lnx)



Homework Equations


I know that the derivative of the function is
f'(x)= 1/(x-xlnx)

but I'm so confused on how to find the asymptotes and the intervals of increase and decrease...



The Attempt at a Solution


Found f'(x) and equated it to zero... but i messed up somewhere.. clueless :S

For A, are there any values of x for which f(x) is not defined? This is related to vertical asymptotes.

As x approaches +inf or -inf, does f(x) approach some specific value? If so, the function has a vertical asymptote. Presumably you did this kind of analysis in the class before calculus.

For B, you have found f'(x). Where is f'(x) > 0? That's where the graph of f is increasing. Where is f'(x) < 0? That's where the graph of f is decreasing.

For C, a good start is finding where f'(x) = 0.
 

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