Feynman Diagram for phi^4 theory (path integral)

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Dixanadu
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Homework Statement


Hey guys!

So basically in the question I'm given the action

[itex]S=\int d^{d}x \left[ \frac{1}{2}\partial_{\mu}\phi\partial_{\nu}\phi\eta^{\mu\nu} - \frac{m^{2}}{2}\phi^{2} -\frac{\lambda}{4!}\phi^{4}\right][/itex].

I have use the feynman rules to calculate the tree level diagram with 6 external momentum states [itex]k_{1},k_{2}\dots k_{6}[/itex]

Homework Equations


Not sure -- please ask if you need something as I have no idea what information is needed

The Attempt at a Solution


As far as I understand, I have to construct the Z function by isolating the vertex. Doing this, i get

[itex]Z[J]=e^{-i\frac{\lambda}{4!}\int d^{d}x\left( i\frac{\delta}{\delta J(x)} \right)^{4}}\int D\phi e^{i\int d^{d}x \left[ \frac{1}{2}\partial_{\mu}\phi\partial_{\nu}\phi\eta^{\mu\nu} - \frac{m^{2}}{2}\phi^{2} -iJ(x)\right]}[/itex].

Now you can further isolate the [itex]Z[J=\lambda=0][/itex] factor to get

[itex] Z[J]=Z[0,0]e^{-i\frac{\lambda}{4!}\int d^{d}x\left( i\frac{\delta}{\delta J(x)} \right)^{4}} e^{-(i/2)\int\int d^{d}x\, d^{d}y J(x)D(x-y)J(y)}[/itex],

where

[itex]D(x-y)=\int \frac{d^{d}k}{(2\pi)^{d}}\frac{e^{ik\cdot(x-y)}}{k^{2}-m^{2}+i\epsilon}[/itex].

Now I'm stuck. I don't know how many vertices I should consider, or even what to do with the 6 momenta. I don't know why this is all d-dimensional or how to deal with it.

Help please :D thanks!
 
on Phys.org
Hi.
First of all, you probably studied φ3 theory (if not, do so by all means!), so it would be a very good idea to go back there and see how you can deduce the φ4 analog. (For example, vertices are related to the power of your functional derivative, which is related to the exponent of the interaction term –the one controlled by λ here– in the Lagrangian. In φ3 a vertex connects 3 lines...)
To construct the tree-level diagrams, use Feynman rules: you must have some kind of table or detailed prescriptions in your textbook and you must have read it if you are given such a problem. Then again, use the analogy with φ3...