Yuqing
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While looking for interesting problems, I was led to a problem involving infinite pulleys.
The problem and solution can be found http://www.feynmanlectures.info/solutions/infinite_pulleys_sol_1.pdf" . Now I follow the solution up to the part where he claims \frac{1}{4^{i}M_i} is always vanishing (tends to 0) as i approaches infinity. This does not seem valid.
From M_{i-1} = \frac{4M_{i}t^{i-1}}{M_i + t^{i-1}} we have
M_{i-1}=\frac{4t^{i-1}}{1 + \frac{t^{i-1}}{M_i}}
Since we know \frac{t^{i-1}}{M_i} \ge 0 we then have
M_{i-1} \le 4t^{i-1} or equivalently
M_i \le 4t^i
from this we can get
\frac{1}{4^{i}M_i}\ge \frac{1}{4}\cdot\frac{1}{4^{i}t^{i}}
so that \frac{1}{4^{i}M_i} is vanishing only if \frac{1}{4^{i}t^{i}} is. I'm not sure how to determine the actual convergence of the Mis and I might be missing something but this solution does not seem to be valid because of the above point. Does anyone know of a way to perhaps salvage this solution?
The problem and solution can be found http://www.feynmanlectures.info/solutions/infinite_pulleys_sol_1.pdf" . Now I follow the solution up to the part where he claims \frac{1}{4^{i}M_i} is always vanishing (tends to 0) as i approaches infinity. This does not seem valid.
From M_{i-1} = \frac{4M_{i}t^{i-1}}{M_i + t^{i-1}} we have
M_{i-1}=\frac{4t^{i-1}}{1 + \frac{t^{i-1}}{M_i}}
Since we know \frac{t^{i-1}}{M_i} \ge 0 we then have
M_{i-1} \le 4t^{i-1} or equivalently
M_i \le 4t^i
from this we can get
\frac{1}{4^{i}M_i}\ge \frac{1}{4}\cdot\frac{1}{4^{i}t^{i}}
so that \frac{1}{4^{i}M_i} is vanishing only if \frac{1}{4^{i}t^{i}} is. I'm not sure how to determine the actual convergence of the Mis and I might be missing something but this solution does not seem to be valid because of the above point. Does anyone know of a way to perhaps salvage this solution?
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