Field due to point charges - extremely strange error

AI Thread Summary
The discussion revolves around finding the electric field on the x-axis due to two point charges, Q and -Q, positioned at specified coordinates. The original poster is struggling to arrive at the correct answer despite reviewing their calculations with peers. They express frustration, humorously suggesting they've "ruined the laws of physics." Participants point out errors in the setup of vector components and suggest simplifying the problem by combining fractions for clarity. The conversation emphasizes the importance of accurately calculating the z-component of the electric field and correcting any mistakes in the numerator of the equations.
Ngineer
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Homework Statement


Find electric field anywhere on the x-axis due two two point charges
Q at (0,0,d)
-Q at (0,0,-d)

Homework Equations

The Attempt at a Solution


AttachedSomehow I am not getting the correct answer. I reviewed my steps with 4 people and we could not find the error!

I'm starting to think I've ruined the laws of physics.
 

Attachments

  • WP_20141010_002.jpg
    WP_20141010_002.jpg
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Because you know one charge to be -Q then I would expect on the diagram you'd show its field line vector directed towards the charge.
 
Ngineer said:

Homework Statement


Find electric field anywhere on the x-axis due two two point charges
Q at (0,0,d)
-Q at (0,0,-d)

Homework Equations

The Attempt at a Solution


AttachedSomehow I am not getting the correct answer. I reviewed my steps with 4 people and we could not find the error!

I'm starting to think I've ruined the laws of physics.

What is the z-component of E?
 
N.O. - The change in sign and direction was accounted for on the second line.
berkeman - the answer I got was -2q/4piEo * 1/(x2 + d2) az which is different from the "correct" answer by a factor of d/(x2 + d2)
 
It is hard to read that image.

You set up a vector and then write "=0." If that would be true, there would be nothing left to calculate.

Where do you calculate the z-component of your force?
 
Please discard that =0

I rewrote the solution for clarity
 

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  • WP_20141010_004.jpg
    WP_20141010_004.jpg
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P/S. There a missing 2 one line before the end but it should be obvious
 
I don't see what you did in the numerator between the first and second line. Your new numerator has both a different magnitude and direction.
You can make this way easier by combining the fractions and sorting the numerator by x and z components.
 
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