Field of a moving eletron

  • Thread starter gstrosx
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Homework Statement



An electron is moving with a speed of 3*10^6 m/s. What are the directions (NE, N, NW,..., In the screen, out of the screen, zero magnitude) of the electric and magnetic field. What is the magnitude of the electric and magnetic field?
Code:
     moves this direction 3e6
     /
    / angle = 60 degrees
electron-------------------------Observation location, d = 3e-10

Homework Equations



for field direction the right hand rule is applicable

E=N/C
B=T

The Attempt at a Solution


Efield is similar to a Efield from a electric circuit, applying the right hand rule in the opposite direction of the movement of the electron gives out of the screen.

Mfield is, at a speratic guess (using a left hand rule i think) is East

|E|=1/4pi epsilon naught * chargeOfelectron/d^2

|B|=googly eyes.
 

Answers and Replies

  • #2
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You're confusing the direction of the E-field with that of the B-field. Remember that the E-field due to a point charge is
[tex]\textbf{E}=\frac{Q}{4\pi \epsilon_0 r^2}\ \hat{\textbf{r}}[/tex]​
and the B-field due to a point charge is
[tex]\textbf{B} = \frac{\mu_0}{4\pi} \frac{q\textbf{v} \times \hat{\textbf{r}}}{r^2}[/tex]​
 

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