Since you are told that the flow rate is constant, the volume of water through the pipe in one second
is the flow rate.
Don't worry about these terms right now. I am trying to get you off your dependence on memorizing equations.
... that's the volume of a cylinder radius r and length h - good.
(It's better if you use "π" instead of "∏" there, but I can see what you mean.)
∏(.325m)^2(.65m)=.2157m^3
You used r=0.325m and h=0.65m ... why? Where do these figures come from?
How does this tell me the flow rate per second?
If the numbers you use have no relation to the problem then it won't of course.
The pipe is cylindrical with diameter d=0.48m
The water flows in the pipe at speed v=22m/s
The water leaving the pipe is basically a cylinder that grows in length... or it would be if it didn't fall etc. So imagine water pouring out the pipe in a long straight cylinder of water. You can work out the volume of the water leaving the pipe by working out the volume of the "cylinder" of water.
I'm asking you to use these figures, and the equation for the volume of a cylinder, to work out the volume of water that left the pipe in 1 sec.
If you know the volume of water that flows out the pipe in 1 second, then you can work out howm many seconds are needed to fill the tank.