Filling in piecewise function from given graph

AI Thread Summary
Understanding piecewise functions can be challenging, especially when trying to fill in values from a graph. To start, it is essential to identify the values of y at specific x points, such as x = -3 and x = -2, to establish the correct equation. The suggested approach using the formula y - y1 = m(x - x1) can help find the line segments between these points. Observing the graph closely will clarify the function's values at critical points, particularly for x ≥ 1. Familiarity with basic function concepts, often covered in introductory calculus, is crucial for solving these types of problems effectively.
Niaboc67
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Homework Statement


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Homework Equations



The Attempt at a Solution

Not sure what to do here. I was thinking maybe the y y1 = m(x x1)? I am having trouble understanding this question. I know what piecewise functions are but filling this in is proving difficult.
 
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Niaboc67 said:

Homework Statement

Homework Equations



The Attempt at a Solution

Not sure what to do here. I was thinking maybe the y y1 = m(x x1)? I am having trouble understanding this question. I know what piecewise functions are but filling this in is proving difficult.
Start with x<=-2. What is the value of y at x=-3? What is its value at x=-2. What equation of the form you suggest passes through those two points?
 
Lift your morale by doing the easy parts first. It is pretty clear on the graph what x and f(x) (which maybe you think of as the 'y axis') are meant to be at the points represented by blobs. You can't have any difficulty then in knowing what f(x) is when x ≥ 1 surely?

Edit :I am quite often surprised when students come here asking questions about what is in the first section of Chapter 1 of every book on the subject. This looks like the explanation of what is meant by 'a function' which is typically in that chapter of every book on calculus. 50:1 a very similar example is at the end of that first section in your book.
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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