Filter Network - (answer does not match books)

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SUMMARY

The discussion centers on the correct formulation of the transfer function for a filter network, specifically the equation for \(\bar G_v(j \omega)\). The correct equation is identified as \(\bar G_v(j \omega) = \frac{j \omega C (R_1+R_2)+1}{j \omega R_1 +1}\). Additionally, the participant emphasizes the importance of Kirchhoff's Current Law (KCL) in deriving the nodal equation, stating that the sum of currents at a node must equal zero, leading to the equation \(Vi/a + (Vi-Vo)/b = 0\).

PREREQUISITES
  • Understanding of transfer functions in electrical engineering
  • Familiarity with Kirchhoff's Current Law (KCL)
  • Knowledge of filter network design principles
  • Basic proficiency in complex frequency analysis
NEXT STEPS
  • Study the derivation of transfer functions in filter networks
  • Learn about Kirchhoff's Current Law (KCL) applications in circuit analysis
  • Explore advanced filter design techniques using operational amplifiers
  • Investigate the impact of component values on filter performance
USEFUL FOR

Electrical engineers, students studying circuit theory, and professionals involved in filter design and analysis will benefit from this discussion.

FrogPad
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I'm not sure what I'm doing wrong here, as my answer does not match up with the books. Sorry about the scan, it looks kinda bad.

! I made a mistake writing the books answer down. It should be:

[tex]\bar G_v(j \omega ) = \frac{j \omega C (R_1+R_2)+1}{j \omega R_1 +1}[/tex]
Any help would be awesome! Thanks!

186200375_23e99d99bb_o.jpg
 
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You sure it's not:

[tex]\bar G_v(j \omega ) = \frac{j \omega C (R_1+R_2)+1}{j \omega C R_1 +1}[/tex]

Anyway, I think your nodal equation is incorrect. KCL states that the sum of all currents flowing out of the node equals to zero. Vi/a and (Vi-Vo)/b are both currents flowing out of the node. So it's supposed to be Vi/a + (Vi-Vo)/b = 0.
 
:blushing:

slapping myself in the head :smile:

Thanks Rumpelstiltzkin !
 

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