Final answer: How fast does the block of wood move after being hit?

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SUMMARY

The discussion centers on the application of the conservation of linear momentum to determine the velocity of a block of wood after being struck by a bullet. A 10g bullet traveling at 400 m/s hits a block of wood and exits at 350 m/s. The correct formula used is mv of the bullet + mv of the block = mv' of the bullet + mv' of the block, leading to the conclusion that the block moves at 0.25 m/s after the impact. It is emphasized that including units in the final answer is crucial for clarity and accuracy.

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  • Understanding of linear momentum conservation principles
  • Basic knowledge of mass and velocity calculations
  • Familiarity with unit conversions, particularly grams to kilograms
  • Ability to apply algebraic equations to solve physics problems
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  • Learn about elastic vs. inelastic collisions and their implications
  • Explore the effects of mass differences in collision outcomes
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This discussion is beneficial for physics students, educators, and anyone interested in understanding momentum and collision dynamics in mechanics.

chibichibi7554
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I am not sure if I am doing this question right.

A 10g bullet, traveling at 400 m/s hits a block of wood & emerges going at 350 m/s. How fast goes the block of wood move after being hit?

Is this the right way to solve it?:

mv of the bullet + mv of the block = mv' of the bullet + mv' of the block
(.01)(400)+0=(.01)(350)+(2)v
v=.25
 
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You left the mass of the block out of your problem statement but included it in the work as 2kg (right?). Other than that it looks like a correct application of the conservation of linear momentum. Oh, and be sure to include units on the answer -- many folks (including me) will mark you down for leaving them off.
 

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