Final Exam Help: Converging Lens and Light Bulb

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To determine where to place a screen for a converging lens with a focal length of 15.0 cm positioned 53 cm from a light bulb, the lens formula is essential: 1/d_i + 1/d_0 = 1/f. Here, d_0 is the object distance (53 cm) and f is the focal length (15 cm). By rearranging the formula, the image distance (d_i) can be calculated. This calculation will indicate the correct position for the screen to focus the image of the light bulb. Understanding and applying this formula is crucial for solving the problem effectively.
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Woo, this is on my final exam and i don't know if there's a formula or something to solve it. really need help. anything is appreciated.

A converging lens with a focal length of 15.0 cm is placed 53 cm from a light bulb. Where would you place a screen to focus an image of the object? :rolleyes:
 
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ajc9387 said:
Woo, this is on my final exam and i don't know if there's a formula or something to solve it. really need help. anything is appreciated.

A converging lens with a focal length of 15.0 cm is placed 53 cm from a light bulb. Where would you place a screen to focus an image of the object? :rolleyes:
click the link below to see a drawing. do you recall how to apply the formula below from your textbook?

http://img31.echo.cx/img31/1521/img12642ah.png

\frac{1}{p} \ + \ \frac{1}{q} \ = \ \frac{1}{f}
 
In case those variables were confusing, I rewrote them.

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

d_0 = object distance
d_i = image distance
f = focal length
 

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