Final temperature after calories are added

AI Thread Summary
To find the final temperature of a 60.5g piece of lead after adding 328 calories of heat, the equation Q = mCΔT is applicable, where Q is the heat added, m is the mass, C is the specific heat capacity of lead, and ΔT is the change in temperature. The user is advised to ensure that units are consistent throughout the calculation. The specific heat capacity of lead is necessary for accurate results, and the final temperature can be calculated by rearranging the equation to solve for the final temperature. Clarification on how to incorporate the heat value into the equation is requested, indicating a need for step-by-step guidance. Understanding these principles will lead to the correct final temperature calculation.
Knfoster
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Homework Statement



A 60.5g piece of lead is at 18.6oC. If 328 cal of heat is added to the lead, what is its final temperature? Do not enter units.

Homework Equations


I was trying to use 328 as the Q value and solve for delta T
Q=mCdelta T
HOWEVER, this wasn't working.



The Attempt at a Solution


Could someone please explain to me what equation I need to use and how the 328 cal are used? Thanks.
 
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Can you show your calculation? You say you solved for deltaT but you need to go one step further and find the final temperature. If you did that, are you making sure your units are consistent? What are you using for C?
 
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