Find a g=a+bx that is orthagonal to the constant function

Cassi
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Homework Statement


In the real linear space C(1, e), define an inner product by the equation (f,g) = integral(1 to e)(logx)f(g)g(x)dx.
(a) If f(x)=sqrt(x), compute ll f ll (the norm of f)
(b) Find a linear polynomial g(x)=a+bx that is orthagonal to the constant function f(x)=1

Homework Equations



The Attempt at a Solution


I have solved part (a) and found that ll f ll = 1/2sqrt(e2+1) but I am having trouble with part B.

I see that the answer is b[x-(e2+1)/4] but I cannot get this answer. I know that (f, g) = 0 but I do not know how to solve this.
 
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Cassi said:
I know that (f, g) = 0 but I do not know how to solve this.
Did you apply the definition of the inner product to this equation? Then you can solve it and get conditions for a and b.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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