Find a point on the axis of a parabola

AI Thread Summary
The discussion focuses on proving the existence of a specific point K on the axis of the parabola y^2 = 4ax, where the expression (1/PK^2) + (1/QK^2) remains constant for any chord PQ passing through K. The coordinates of point K are identified as (-at1t2, 0). Participants express difficulty in proving the independence of the expression from parameters t1 and t2, despite having established the coordinates of K. Suggestions include considering the chord as a normal at point P and exploring relationships with tangents at points P and Q. The goal is to find the conditions on K that validate the theorem's claim.
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Homework Statement



Prove that on the axis of any parabola y^2 = 4ax there is a certain point K which has the property that,if a chord PQ of the parabola be drawn through it ,then \frac{1}{PK^2} + \frac{1}{QK^2} is same for all positions of the chord.Find aslo the coordinates of the point K


Homework Equations



We can apply the parametric equations of a parabola.


The Attempt at a Solution



Let the points P and Q be (at_{1}^2,2at_{1}) and (at_{2}^2,2at_{2})

So the equation of the chord would be y(t_{1} + t_{2}) = 2x + 2at_{1}t_{2}

Hence from there we have that the points of K are (-at_{1}t_{2},0)

Now our aim is to show that \frac{1}{PK^2} + \frac{1}{QK^2} is independent of t_{1} and t_2{}. I tried and applied the distance formula but no benefit.
 
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The theorem says that there exists such a point K. What are the conditions on K that will make \frac{1}{PK^2} + \frac{1}{QK^2} independent of t1 and t2?
 
HallsofIvy said:
The theorem says that there exists such a point K. What are the conditions on K that will make \frac{1}{PK^2} + \frac{1}{QK^2} independent of t1 and t2?

Yes they are saying that there exists such a point that \frac{1}{PK^2} + \frac{1}{QK^2} is same for all positions of that point and we have to prove this.
 
My point was that you said:
FedEx said:
Now our aim is to show that \frac{1}{PK^2} + \frac{1}{QK^2} is independent of t_{1} and t_2{}. I tried and applied the distance formula but no benefit.


without any conditions on K. You are not asked to show that but rather find the single point K for which that is true.
 
Agreed. But we also have to prove that. The question says "Prove that on the axis of any parabola ...coordinates of the point K.

And let's forget about that for a minute, i have shown that the coordinates of the point k would be (-at_{1}t_{2},0).

So that is done.

But when it comes to proving,i am completely at sea.

But i think we can consider that chord to be a normal at the point P. If we do so we can get the equation of the normal as

y = -t_{1}x + 2at_{1} + at_{1}^3 and at the same time we can also consider the equation of the tangent passing through P and than we can consider a tangent at Q which will intersect the tangent at P and then we MAY get some relation.
 
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