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Homework Statement
Function: f(x)=x^2-x Line: x+2y-6=0
The Attempt at a Solution
Find an equation of the line that is tangent to the graph of f and parallel to the given line.
RPierre said:First, you must simplify your line for y = mx + b form.
x + 2y - 6 = 0
-> x - 6 = -2y
-> [tex]\frac{x-6}{-2}[/tex] = y
-> y = [tex]\frac{-1x}{2}[/tex] + 3
Next, to find a line tangent to f(x), we take it's derivitive
f'(x) = 2x - 1
Compare the two slopes. 2 and -1/2. These are in fact perpendicular to each other. See what you can do with that.
The equation of a line is a mathematical representation of a straight line on a graph. It is typically written in the form y = mx + b, where m is the slope of the line and b is the y-intercept.
To find the equation of a line, you need to know at least two points on the line. Then, you can use the slope formula (m = (y2-y1)/(x2-x1)) to find the slope and the point-slope formula (y-y1 = m(x-x1)) to find the equation of the line.
No, you need at least two points to find the equation of a line. With only one point, you can determine the slope of the line but you cannot determine the y-intercept or the specific equation.
If the line is not a straight line, then it is not possible to find a single equation that represents the entire line. However, you can still find the equation of a line segment or a curve by using a different mathematical formula or method.
Yes, you can use any two points on a line to find the equation as long as they are not the same point. The two points must also be distinct (not on top of each other) in order to determine a unique slope and equation.