The area of a rectangle can be calculated using the formula A = length x width. Given that the length is x and the width is 8 - x, the area can be expressed as A = x(8 - x). Expanding this equation results in A = 8x - x². The discussion highlights confusion regarding the initial problem statement, indicating that additional information may be needed for clarity. Ultimately, the relationship between length, width, and area is confirmed through algebraic expansion.
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tayross
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if the length of a rectangle = x,
show that the area of the rectangle is given by A = 8x - x[2]
Neither do I, there must be some information you are not giving us.
Please post the entire question.
Other than that, let us assume for a moment that we know that the length of a rectangle is x and its width is 8 - x.
Then do you agree that its area must be x(8 - x)?
Do you see how opening the brackets gives 8x - x2?
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached.
The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter.
From my side, the only thing I could...