Find critical points, please share any tricks you know of

This will help you to find the minimum point.In summary, to find the minimum point of the given function, you will need to compute the gradients and complete the squares in the exponents after expanding all terms and performing the integrations. This will allow you to find the minimum point.
  • #1
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1. Find the minimum point of
[tex]I(p, q, r, s)=\int_{\mathbb{R}^2}\,dxdy\,\left[exp(-(x-d)^2-y^2)+exp(-(x+d)^2-y^2)-exp(-(x-p)^2-(y-q)^2)-exp(-(x-r)^2+(y-s)^2)\right]^2[/tex]
[tex]+\int_{\mathbb{R}^2}\,dxdy\,\left[exp(-(x-\delta_x)^2-(y-\delta_y)^2)-exp(-(x-p)^2+(y-q)^2)\right]^2[/tex]
for given [tex]d, \delta_x, \delta_y[/tex].

The Attempt at a Solution


i don't have any ideas how to tackle this problem in a intelligent manner. what else can one do beyond calculating the gradient with respect to p, q, r, s?

thanks for any assistance
 
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  • #2
You will have to compute the gradients to find the critical points. But you should definitely do all the integrations first. You need to expand all terms and then complete the squares in the exponents.
 

1. What are critical points?

Critical points are points on a graph where the derivative of the function is equal to zero, or where the derivative is undefined. They are important because they can help us identify where the function changes direction, and can be used to find the maximum and minimum values of a function.

2. How do I find critical points?

To find critical points, you can take the derivative of the function and set it equal to zero. Then, solve for the variable. Another method is to graph the function and look for points where the graph changes direction or has a flat tangent line.

3. Can I use the second derivative test to find critical points?

Yes, the second derivative test can be used to confirm if a point is a maximum, minimum, or neither. If the second derivative is positive, the critical point is a minimum. If the second derivative is negative, the critical point is a maximum. If the second derivative is zero, the test is inconclusive.

4. Are there any tricks for finding critical points quickly?

One trick is to look for symmetry in the function. If the function is even, the derivative will be odd and the critical points will be where the derivative crosses the x-axis. If the function is odd, the derivative will be even and the critical points will be where the derivative is equal to zero.

5. Can critical points only exist in the domain of a function?

Yes, critical points can only exist in the domain of a function. However, a function can have critical points that are not in the domain, known as asymptotes. These points are still important to consider when analyzing the behavior of the function.

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