Find David's Velocity w/ Respect to John: Relative Velocity Homework

AI Thread Summary
To find David's velocity with respect to John at t=1, differentiate both equations of motion to obtain their velocities. John's velocity is derived from Rj(t) = (t^2 + 3t)i + tj, resulting in vj(t) = (2t + 3)i + j. David's velocity from Rd(t) = 5ti + t^3j gives vd(t) = 5i + 3t^2j. At t=1, calculate both velocities and then determine the relative velocity by subtracting John's velocity from David's. This approach clarifies the process of finding relative velocity in motion problems.
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Homework Statement


John equation of motion is Rj(t)=(t^2+3t)i + tj. David's equation of motion is Rd(t)=5ti+t^3j. At t=1 find David's velocity with respect to john.


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The Attempt at a Solution

I know if you plug in the one that will give you the position they are both at when t=1. Where do I go from there to find their velocity?
 
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It's a dead end if you plug in t=1 in the first place. Instead, you should differentiate the positions with respect to time to find the velocities. Hint:
\frac{d}{dt} (x^n) = nx^{n-1}
 
Ok, that makes a lot more sense! I believe that's going to help me out! Thanks. I was just totally looking past that.
 
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