Find Distance Traveled From 40m Height for 20m/s Velocity at 0° Angle

[Gliese123]

Homework Statement

From a height 40 meters up, one throw a ball with the velocity of 20 m/s. The elevation is 0°. How far does the ball come?

v_o = 20 m/s
x = 40 meters
α = 0°
(g=9.82)

Homework Equations

y = v₀ × t × sinα - (9.82×t²)/2

x= v₀×t×cosα

The Attempt at a Solution

I put what I know in there

40 = 20×t×sin0° - (9.82×t²)/2
=>
80/9.82 = t²
=>
√(80/9.82) = t = 2.85 s (Is that right?)

Then I put all I know in the other formula to get x:
x= v₀×t×cosα

x = 20×2.85×cos0°
x=57 meters
(Doesn't that feel a little too short?)

I've no answer to this question and I would be really glad if someone could confirm that this is correct calculated :)
Edit: There's no air resistance

 

[Doc Al]

Looks good to me.

 

[Gliese123]

Looks good to me.

I hope so. Thanks for checkin' it :)