Find eccentricity of orbit of comet

AI Thread Summary
To find the eccentricity of a comet's orbit, the distance between the foci and the length of the major axis are essential. The comet's perihelion (closest distance to the Sun) is 0.5 AU, and its aphelion (farthest distance) is 50 AU. The eccentricity can be calculated using the formula e = (aphelion - perihelion) / (aphelion + perihelion). Understanding the relationship between perihelion, aphelion, and the foci is crucial for solving the problem. This discussion highlights the importance of using the correct formulas and definitions in orbital mechanics.
moondawg
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Homework Statement


Find eccentricity for: a comet with mass 1.2x1010kg moves in an elliptical orbit around the sun. Its distance from the Sun ranges between .5AU and 50 AU.



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The Attempt at a Solution


I drew it out to try and viualize it and i know eccentricity is the distance between the foci divided by length of major axis but how do i find the foci?! So confused and I know this problem is probably extremely easy please help!
 
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hi moondawg! :smile:
moondawg said:
Its distance from the Sun ranges between .5AU and 50 AU.
…
¬ i know eccentricity is the distance between the foci divided by length of major axis but how do i find the foci?! So confused and I know this problem is probably extremely easy please help!

yes, https://www.physicsforums.com/library.php?do=view_item&itemid=96" = f/a …

hint: what are perihelion and aphelion in terms of f and a ? :wink:
 
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