Find Force Exerted on Blocks Sliding Down a Rough Incline

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The discussion focuses on calculating the acceleration of two blocks sliding down a rough incline and the force exerted by the lighter block on the heavier one. The blocks have masses of 2.500 kg and 3.100 kg, with coefficients of friction of 0.2300 and 0.5100, respectively, on a 30-degree incline. One participant calculated the acceleration to be approximately 1.6336 m/s² but is uncertain about determining the force on the second block. They attempted to sum the forces acting on both blocks, factoring in gravity and friction, to find the overall acceleration. The conversation emphasizes collaboration, encouraging others to share their work without completing it for them.
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Two blocks (m1 = 2.500 kg and m2 = 3.100 kg) slide down a rough 30.0 degree incline.
µ1 = .2300 for the lighter block
µ2 = .5100 for the heavier block
a) Determine the acceleration of the pair.



b) Calculate the force the lighter block exerts on the heavier one.

there is a picture as an attachment (couldn't figure out how to just put it on).

i think i have found the acceleration of the objects i got 1.6336 meter per second squared but i don't know how to find the force on the second object.

I took the sum of the forces which included (m1)(gravity)(sin30)-friction on that object + (m2)(gravity)(sin30)- friction of that object) all over (m1 + m2). to get 1.6886
 

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what work have you done so far? We can help put you in the right direction, but we won't do all of your work for you
 
i think i have found the acceleration of the objects i got 1.6336 meter per second squared but i don't know how to find the force on the second object.

I took the sum of the forces which included (m1)(gravity)(sin30)-friction on that object + (m2)(gravity)(sin30)- friction of that object) all over (m1 + m2). to get 1.6886
 
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