Find Image of f: III2 Additive Group of Integers Mod 12

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Homework Statement


Consider III2, the additive group of integers modulo 12, and let f : II12 -->II12 be defined by f(x) = 3x. Find imf.


Homework Equations


II12 = {1,2,3,4,5,6,7,8,9,10,11,12}
II12 / ker f is isomorphic to image of f


The Attempt at a Solution


I don't know were to begin.
 
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Why don't you just compute 3x for all x in III2 and see what you get?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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