1. The problem statement, all variables and given/known data A flowerpot falls from the ledge of an apartment building. It takes .2 s for the pot to pass the 4 m window below. How far above the top of the window is the ledge from which the pot fell? (Neglect air resistance) 2. Relevant equations y(t)=y0 + (voy)(t) - 1/2g(t^2) vy(t) = voy - gt 3. The attempt at a solution 4m/.2s =20m/s so vy(.2)=voy-(9.81*.2) 20+1.962= voy 22= initial velocity y(t)=y0 + 22(.2)-(9.81/2)(.2^2) 0 = y0 +4.4 - .2 Yeah, I know I'm wrong I just can't figure out how to do this problem.