- #1
knowLittle
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Homework Statement
y= (x^2 -7) e^x
The Attempt at a Solution
I'm trying to find inflection points by setting the second derivative=0
I found that the derivative is:
##2xe^{x}+x^{2}e^{x}-7e^{x}=0##
##e^{x}[2x+x^{2}-7]=0##
Then, the 2nd derivative:
##e^{x}[(x-1)(x+5)]=0##, then the inflection points are at x=- infinity; 1; -5.
Where ##e^{x}=0 ##, happens when x=-infinity
Is it correct to use - infinity as a value of x ?
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