Find Largest Focal Length Lens for Photo of Poster - 2.79mm

AI Thread Summary
To determine the largest focal length lens for photographing a poster, the maximum distance from the camera to the poster is 3.1 m, with the poster dimensions being 0.8 m wide and 1.2 m tall. The film frame size is 24 x 36 mm. The initial approach involved calculating the area ratio of the poster to the film, which led to confusion. The correct method is to use the ratios of the sides for magnification, ultimately leading to a focal length calculation of -2.79 mm. This emphasizes the importance of using appropriate dimensions rather than area ratios in lens calculations.
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Homework Statement



You take a picture of a poster on the wall of a room and maximum distance you can get from the picture is 3.1 m. The poster is 0.8 m wide and 1.2 m tall and you want it to fit in the 24 x 36 mm frame of the film in your camera.

What is the largest focal length lens that you can use? ____mm

Homework Equations



1/f = 1/do + 1/di
M=-di/do



The Attempt at a Solution



I have absolutely no idea how to go about this. What I tried, for starters, was find the ratio of the areas of the poster (0.96m^2) and the film (8.64E-4 m^2). I thought that by finding the ratio of the film to the poster would give me magnification which was equal to 9E-4. Then, using this number, I used the equation M=-di/do, plugged in 9E-4 for M and 3.1 for do and tried solving di and got -0.00279m. Then, I plugged this in the equation 1/f=1/do +1/di to solve for f and I got: 1/f=(1/3.1)+ -(1/.00279) = (-358.1 m) and took the inverse to be -0.00279 m. Then, converting to mm, it was -2.79mm.
 
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Don't use the ratios of the areas. Use the ratios of the sides.
 
Thank you very much. I finally got it!
 
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