Find Limit of Fibonacci Sequence | Determine L

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Let f_{n} be the Fibonacci sequence and let x_{n} = f_{n+1}/f_{n}. Given that lim(x_{n})=L exist determine L.

Ok so I know that the limit is \frac{1+\sqrt{5}}{2} from previous experience with the sequence, but I am not sure how do you show that without writing out a lot of terms and then noticing what I all ready know it is. How do you find the limit of a sequence to a number if your not given any numbers to work with?
 
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Hi Punkyc7 ! :smile:

If there is a limit, then you can assume that xn = xn-1 :wink:
 
true, but how do you ever get a number when you are dealing with f_{n} and f_{n+1}. How can you just make a jump and say there is a \sqrt{5} in there
 
Punkyc7 said:
How can you just make a jump and say there is a \sqrt{5} in there

quadratic equation? :wink:
 
Ok I am not sure how you got there but this is what I have so farlet x_{n} = f_{n+1}/f_{n} and let lim(x_{n})=L. From here is where I get stuck. I know that every sub sequence of a convergent sequence converges to the same number by some theorem, but I am not sure how that is at all helpful.

Would you do something like
x_{n} = f_{n+1}/f_{n}
x_{n-1} = f_{n}/f_{n-1}
 
put xn = xn-1
 
Ok so you get

= f_{n}/f_{n-1} = f_{n+1}/f_{n}

I think I see where you got the quadratic equation now

f_{n} ^2= f_{n-1} f_{n+1}=f_{n} ^2 - f_{n-1}( f_{n+1})to use the quadratic equation is this f_{n-1}( f_{n+1}) considered b or c?

and that doesn't look very pretty to solve...
 
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erm :redface:

you'll also need fn+1 = … ? :wink:
 
Ok

f_{n+1}=\frac{f_{n}}{f_{n-1}}


f_{n} ^2 - f_{n-1}* \frac{f_{n}}{f_{n-1}}

f_{n} ^2 -f_{n}=0

is that right?
 
  • #10
This is the Fibonacci sequence!

So fn+1 = ? :smile:
 
  • #11
oh so
f_{n+1}= f_{n} +f_{n-1}


do I use that for f_{n+1}
Also how do you know when to use what?
 
  • #12
Punkyc7 said:
do I use that for f_{n+1}

yes … that should give you your quadratic equation :wink:
Also how do you know when to use what?

You're told it's a Fibonacci sequence, so you obviously have to use that information somewhere! :smile:

and now I'm off to bed :zzz:
 
  • #13
let x_{n} = f_{n+1}/f_{n} and let lim(x_{n})=L. Since we know the sequence converges we can say

x_{n} =x_{n-1} Which Implies

= f_{n}/f_{n-1} = f_{n+1}/f_{n}

f_{n} ^2= f_{n-1} f_{n+1}=f_{n} ^2 - f_{n-1}( f_{n+1})=0

f_{n} ^2 - f_{n}f_{n-1}-f_{n-1}^2=0How do you hammer this into the quadratic equation I am thinking the a=1 b=not sure c=not sure ? Also how do you get numbers from this when we don't have a single number?
 
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  • #14
Punkyc7 said:
let x_{n} = f_{n+1}/f_{n} and let lim(x_{n})=L. Since we know the sequence converges we can say

x_{n} =x_{n-1} Which Implies

= f_{n}/f_{n-1} = f_{n+1}/f_{n}
...which also equals L:

\frac{f_n}{f_{n-1}} = \frac{f_{n+1}}{f_n} = L

Now take this portion:
\frac{f_{n+1}}{f_n} = L

Replace the numerator with its equivalent, and then rewrite as a sum of two fractions. A substitution can be made, and you will end up with an expression on the left side with NO f's. Soon you will see a quadratic equation in terms of L. Solve for L.
 
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