- #1
pureouchies4717
- 99
- 0
hi, can someone please look at this. it doesn't look right to me. thanks
i have to find the limit:
a(1)= 2 a(n+1)=1/(3-an)
a1=2, a2=1, a3= .5, a4= .4, a5= .3846, a6=.382385... a9=.3819742, a10= .3819672
therefore the limit would be approximately .38197 right?
i have to find the limit:
a(1)= 2 a(n+1)=1/(3-an)
a1=2, a2=1, a3= .5, a4= .4, a5= .3846, a6=.382385... a9=.3819742, a10= .3819672
therefore the limit would be approximately .38197 right?