Find magnetic flux density B circulation in closed contour

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SUMMARY

The discussion focuses on calculating the magnetic flux density B circulation in a closed contour consisting of a larger square perimeter of 4b and a smaller square conductor with a perimeter of 4a. The solution involves applying Ampere's law, leading to the equation ∫ΓB⋅dl=μ0⋅j⋅a², where the integration contour Γ is crucial for determining the circulation. Key insights include that the line integral of H over any section of the larger perimeter with zero current equals zero, and the circulation of H over the current-carrying sections results in a total of 2ja³. Ultimately, the relationship B = μ0H is established.

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Homework Statement


Find magnetic flux density B circulation in closed contour. The countour consists of square with a perimeter of 4b. It includes a square conductor with a perimeter of 4a. A homogenic current flows through a conductor with a current density of j.
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Homework Equations


∫B⋅dl=μ0⋅I[/B]

The Attempt at a Solution


I get this equation ∫B⋅dl=μ0⋅j⋅a2 but the answer says that the integration contour is Γ. How do I get the Γ? ΓB⋅dl=μ0⋅j⋅a2
 
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Well, since it's been nearly 120 hrs (5 days) with no other posters,I will suggest:
(1) line integral of H over ANY section of the large perimeter WITH ZERO CURRENT EVERYWHERE = 0. This includes the two "a" sections common to the large & small perimeters.
(2) line integral over any one of the four current-carrying section sides (by Ampere's law) = ja2(a) = ja3.
(3) Thus the circulation of H over the two common "a" sections = 2ja3 and of course B = μ0H.
(4) Add (3) to (1) and you get the answer of (3).
 

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