Find Magnitude of Magnetic Field Along Bent Wire at Point P

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SUMMARY

The discussion focuses on calculating the magnetic field at point P due to two segments of a bent wire carrying a 31.0 A current. Using the formula B = μ0 * I * L * sin(θ) / (4πr2), the initial calculation yielded a magnetic field strength of 9.74 x 10-8 T for one segment, leading to a total of 1.948 x 10-7 T for both segments. However, the user encountered an error in their calculations and confusion regarding the direction of the magnetic field, which is not directed out of the page as initially thought.

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Homework Statement


A wire carrying a 31.0 A current bends through a right angle. Consider two 2.00 mm segments of wire, each 3.00 cm from the bend. A figure has been included.

Part A) Find the magnitude of the magnetic field these two segments produce at point P, which is midway between them.

Part B) Find the direction of the magnetic field at point P.


Homework Equations



\vec{}B = μ0*I*Lsin(θ)/4∏r2

The Attempt at a Solution



Using the calculation given above:

B = (10^-7)(31A)(2/1000 m)sin(45)/(18/400)
B = 9.74x10^-8

However there are two wires thus, B = 1.948x10^-7

But it says my answer is wrong and I can't pinpoint where I'm going wrong.

Also, for part B, I'm a little confused about the direction the magnetic field is acting in. Is the force of the magnetic field acting pointing towards point P thus indicating that the magnetic field is point out of the page?
 

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Did you square the r in the denominator when you were doing the calculation?

I don't understand your reasoning for the direction of B. But the direction is not out of the page. See if your text or notes explains how to get the direction.
 

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