Find matrix of the linear function

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Homework Help Overview

The discussion revolves around a linear function F mapping from the polynomial space P4 to R5, specifically examining its properties and the implications of a related linear function D. The original poster seeks to find the matrix of a linear function T that satisfies a specific composition of functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the isomorphism of the function F based on dimensionality and explore how to approach part b of the problem by considering the action of the function on basis elements.

Discussion Status

Some participants have provided guidance on how to tackle the problem by suggesting to evaluate the function for individual basis elements. There is acknowledgment of the original poster's reasoning regarding part a, but part b remains a point of confusion with ongoing exploration of the necessary steps.

Contextual Notes

The original poster has indicated they have completed part a but are uncertain about how to proceed with part b. There is an emphasis on working through the problem using specific basis elements.

junsugal
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Homework Statement



Consider the linear function F : P4 -> R5
that sends the basis {1,x,x2,x3,x4} of P4 to the basis {e1,e1,e3,e4,e5} in R5, in that order , that is F(xn)= e(n+1)).
(a) Is this function an isomorphism?
(b) Consider the linear function D : P4-> P4
p(x)->p'(x)

Find the matrix of the linear function T : R5-> R5 such that
(T o F)p(x) = (F o D)p(x)


Homework Equations





The Attempt at a Solution



I solved for part a, but i have no idea how to start on part b
 
Last edited:
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hi junsugal! :smile:

(try using the X2 button just above the Reply box :wink:)

do it for each basis element separately

start with x4

what do you get? :smile:
 
hmm, what do you mean by start with x4?

For part(a) I said that yes the function is isomorphic because P4 and R5 both have dimension of 5. And according to one of the properties of isomorphic, the dimensions of 2 vector spaces should be the same.

Thanks for the tips! :)
 
junsugal said:
hmm, what do you mean by start with x4?

put x = x4 in (T o F)p(x) = (F o D)p(x) :smile:

(and your (a) is ok)
 

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