Find Matrix P and the Diagonal Matrix D

  • Thread starter Thread starter chwala
  • Start date Start date
  • Tags Tags
    Matrix
chwala
Gold Member
Messages
2,825
Reaction score
413
Homework Statement
see attached - refer to part b only (part a was easy)
Relevant Equations
matrices
1712958779566.png


1712958822270.png


For part (b) i was able to use equations to determine the eigenvectors;

For example for ##λ =6##

##12x +5y -11z=0##
##8x-4z=0##
##32x+10y-26z=0## to give me the eigen vector,


##\begin{pmatrix}
1 \\
2 \\
2
\end{pmatrix}## and so on.

My question is to get matrix P does the arrangement of the eigenvector matrices matter?





1712959692049.png


In my arrangement for eigenvectors for ##λ=6,-4,2##

i have,

##P=\begin{pmatrix}
1 & 1& 1 \\
2 & 0 & -1 \\
2 & 2 & 1
\end{pmatrix}##

and my Diagonal matrix is

##D=\begin{pmatrix}
6^5 & 0 & 0 \\
0 & -4^5 & 0 \\
0 & 0 & 2^5
\end{pmatrix}=
\begin{pmatrix}
7776 & 0 & 0 \\
0 & -1024 & 0 \\
0 & 0 & 32
\end{pmatrix}
##
 
Last edited:
Physics news on Phys.org
chwala said:
My question is to get matrix P does the arrangement of the eigenvector matrices matter?
No, but where you place the eigenvectors (i.e., in which columns) will determine P, which will determine ##P^{-1}## which will then determine where the eigenvalues appear on the diagonal matrix D.
 
Mark44 said:
No, but where you place the eigenvectors (i.e., in which columns) will determine P, which will determine ##P^{-1}## which will then determine where the eigenvalues appear on the diagonal matrix D.
Ok bass (boss). :wink: Gday @Mark44 :cool:
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top