Find Momentum & Force of Pellet Penetrating Clay | Physics

  • Thread starter Thread starter Procrastinate
  • Start date Start date
  • Tags Tags
    Momentum
AI Thread Summary
The discussion focuses on calculating the change in momentum and the force acting on an air rifle pellet penetrating clay. The pellet, with a mass of one gram and a velocity of 100 meters per second, penetrates five centimeters and comes to rest in one millisecond. The change in momentum is calculated as 1 x 10^-1 kg·m/s, and the force acting on the pellet is determined to be 1 x 10^2 N. Participants confirm these calculations, agreeing on the results. The discussion concludes with validation of the answers provided.
Procrastinate
Messages
155
Reaction score
0
An air rifle pellet of mass one gram and velocity 100 metres per second penetrates five centimetres into a lump of clay and comes to rest in one millisecond. Assume that the force acting on the pellet when in clay is constant.

Find the magnitude of the change in momentum and the magnitude of the force acting on the pellet.

My answers were 1 x 10-1kgms-1 and 1 x 102N but there aren't any solutions on the page, so I was wondering if I was right?
 
Physics news on Phys.org
Looks like I got it right.I get the same answers as you.:smile:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top