Find P2 on Plane Given P1 & Dist. 3 Units

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If you are given a plane, (x,y,z) = (2,3,0) + s(4,1,5) + t(1,2,6), and you have a point, let's say P1= (2,3,0). How would you find another point on the plane if you know the distance between P1 and the second point is 3 units?
 
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The locus of all points 3 units from a given one is a sphere.

This intersects the given plane in a circle.

So you need additional information to specify the second point you require.
 


Sorry forgot to mention that P1P2 is perpendicular to P1 and P3 (16.25, 0, 0).
 


So do you not now have two unknowns, s and t, and two known points P1 and P3, that you can use to substitute into find s and t and thence P2?
 
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