Find particular solution third order Diff Eq

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To find a particular solution for the third-order differential equation y''' - y = e^x + 7, the user initially proposed a solution of the form y = Ae^x + B, but recognized the need to adjust due to repeated roots in the complementary solution. The correct approach involves using y = Ax^2e^x + Bx^2 to account for the repeated e^x term. The auxiliary equation r^3 - 1 = 0 indicates one real root and two imaginary roots, necessitating a modification of the complementary solution. The particular integral for the e^x term should be xe^x, leading to a refined solution strategy.
Herricane
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Homework Statement



y''' - y = e^x + 7

Homework Equations





The Attempt at a Solution



I used y=Ae^x +B and then I multiplied by x^2 because y_c = c1 + c2 e^x + c3 e^(-x)

the c1 and c2 e^x value repeat. Therefore I got: y= Ax^2 e^x + Bx^2

I got A = 0 and A=1 which is wrong and B=0

Any hints? do I need to add a Cx e^x and then multiply by x^2?
 
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Your auxiliary equation would be r^3-1=0 which would lead to only one real root and two imaginary roots.

Since e^x is on the right side, the particular integral for the e^x on the right would be xe^x.

You will need to change your complementary solution y_c to reflect one real root and two imaginary roots.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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