Find particular solution third order Diff Eq

Herricane
Messages
61
Reaction score
1

Homework Statement



y''' - y = e^x + 7

Homework Equations





The Attempt at a Solution



I used y=Ae^x +B and then I multiplied by x^2 because y_c = c1 + c2 e^x + c3 e^(-x)

the c1 and c2 e^x value repeat. Therefore I got: y= Ax^2 e^x + Bx^2

I got A = 0 and A=1 which is wrong and B=0

Any hints? do I need to add a Cx e^x and then multiply by x^2?
 
Physics news on Phys.org
Your auxiliary equation would be r^3-1=0 which would lead to only one real root and two imaginary roots.

Since e^x is on the right side, the particular integral for the e^x on the right would be xe^x.

You will need to change your complementary solution y_c to reflect one real root and two imaginary roots.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top