Find period of astronaut when Normal force of ship = normal force on earth

AI Thread Summary
To find the period of rotation of a spaceship that creates the same normal force on an astronaut as experienced on Earth, the gravitational acceleration formula g = GMe/Re^2 is used. The relationship between centripetal force and gravitational force leads to the equation N = mg = m(GMe/Re^2) for Earth and N = mac = m(v^2/r) for the spaceship. By rewriting the velocity equation v = 2∏r/T, the period T can be expressed in terms of the spaceship's radius Rs and Earth's radius Re. Substituting the expressions into the period formula yields T = √[(4pi^2)(Rs)(Re^2)/GMe]. This approach effectively demonstrates the equivalence of normal forces in both environments.
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Homework Statement


If the gravitational acceleration at Earth's surface is given by: g = GMe/Re^2, show that the period of rotation of a spaceship needed to make an astronaut feel the same normal force on the ship that they would feel on Earth, when it is given by T = √[(4pi^2)(Rs)(Re^2)/GMe], where Rs is the radius of ship and Re is radius of earth.


Homework Equations



Fc = ma = m(v^2/r)
Fg = gMem/r^2
v = 2∏r/ T

The Attempt at a Solution



Normal force on Earth = normal force on ship
N = mg = m(GMe/Re^2)
Normal force ship on astronaut = mac = m(v^2/r)

Now I'm not sure what to substitute into the Period formula and how to approach this?
 
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Rewrite v = 2∏r/ T into the form T = ... You have an expression for v, and r = Rs. Just substitute in.
 
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