Find Rope Tension for Mountain Climber 695N

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To determine the tensions in the rope for a mountain climber weighing 695 N, the angles of 65 degrees and 80 degrees must be considered. The correct approach involves using the equilibrium equations, specifically summing the vertical forces and resolving the tensions on either side of the climber. The user initially attempted a calculation using Wsin65 + Wsin80 + W = 0 but found it incorrect. An attached image clarifies the scenario, indicating that the tensions in the left and right sides of the rope are unequal due to the climber's position. Accurate calculations will provide the correct tension values for both sides of the rope.
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A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 695 N. As the drawing shows, (The angle at left is 65) she is closer to the left cliff than to the right cliff (Angle to the right is 80), with the result that the tensions in the left and right sides of the rope are not the same. Find the tensions in the rope to the left and to the right of the mountain climber.

I tried Wsin65+WSin80+W=0 and worked my way out from there, it came out wrong.
 
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As which drawing shows? :)
 
Hmmm...i attached the image. I hope you can see it, & help me if its possible.
 

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I've drawn you a picture. Try now.

attachment.php?attachmentid=24201&stc=1&d=1268031892.gif


Note that i just named them the same, but F_rope is different for each rope.
 

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  • rope-tension.gif
    rope-tension.gif
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