2cot2(x)-5cosec(x)=1 for exactly 6 values of x belongs to [0,nπ], then find the minimum value of n. my answer is 5. How i did it.changing cot to cosec and then solving equation it will give something like cosec(x)=3. for x belongs to 0 to 5π it has 6 solutions.. this is question of a class test & answer in test's answer sheet is 6. WHO IS correct. me or answer sheet???????