Find Tension & Reaction Force for Bar with 600N Force Applied at 30 Degrees

[lukasz08]

Tension = 386lb
Bx = 493lb
By = 186lb

I am having trouble trying to determine the tension in the picture. And the x and y component of B

i have a long bar that is 14 feet long. it is connected at 1 end at point B to a pin support and the other end is tied to a rope at point a.point a the rope has a angle of 30 degrees off of vertical. then i have a downward force of 600 N 30 degrees of the vertical 9 feet away from point B. how do i find the tension in the rope ?

the componets of the 600n force are as follows
-600sin30 = -300
-600cos30 = -519.615
if the rope is 5 feet from these componets how would i find the tension ? and what would be the reaction on point B ?

reaction of By = (-600cos30*5ft)/14ft = 185.6lb = 186lb
how do you find Bx and the tension at rope ?

 

[lukasz08]

Does anyone know how to find the answers ?

 

[PhanthomJay]

You determined By apparently by summing moments about A (unless you did it by trial and error). Now sum moments about B to determine Ay (the vertical component of the tension). Or sum the Fy forces = 0 to get Ay. The horizontal forces and rope tension can then be found. How is the rope tension and its vertical component related?

 

[mathmate]

The forces are yet unknown at two points, namely tension T at A and reactions at B.
Take moments about B to find the tension T of the rope.
Once T is know, summing forces in X and Y will give you everything you need to know for the reaction at B.