Find the absolute value of theta 650-theta 420

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SUMMARY

The discussion focuses on calculating the angular separation between two light rays of wavelengths 650 nm and 420 nm using a diffraction grating with 5000 slits/cm. The formula employed is d*sin(theta) = m*lambda, where 'd' is the grating spacing, 'm' is the order of the maximum, and 'lambda' is the wavelength. Participants confirm that by substituting the appropriate values into the formula, one can derive the angles for both wavelengths and subsequently find the absolute difference between them.

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  • Understanding of diffraction grating principles
  • Familiarity with the formula d*sin(theta) = m*lambda
  • Knowledge of wavelength measurement in nanometers
  • Basic trigonometry for angle calculations
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ahazen
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Two rays of light of wavelength 650 nm and 420 nm are normally incident on a different grating. If the grating has 5000 slits/cm, what is the angular separation of of the two light rays' second order maximum.

-Need to find the absolute value of theta 650-theta 420

I know I need to use the formula d*sin(theta) = m*lambda to find each of the angles in degrees -- then subtract

Please help me:):)

Thank you:)
 
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ahazen said:
I know I need to use the formula d*sin(theta) = m*lambda to find each of the angles in degrees -- then subtract
Yes, exactly. What is it that you don't understand? Just plug in the values for d, m, and λ to figure out what θ is.
 


oh, ok:) it makes sense now:) thank you:)
 

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