Find the Answer to the Ball's Velocity Puzzle

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To solve the ball's velocity puzzle, the initial backward angular velocity (wo) must exceed 4Vo/R for the ping pong ball to return with the same velocity (-Vo) while rolling without slipping. The time to return to the original spot is calculated as T = 2Vo/(g*µk), and the angular acceleration is given by α = (3/2)(g*µk)/R. The relationship between angular velocity and time shows that w must be greater than Vo/R. These equations help determine the necessary conditions for the ball's motion.
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please help me!

I will be so happy if someone gives the answer to this question in a while.
A ping pong ball of radius R and mass M is started with an initial speed Vo and a backward initial angular velocity of wo.The coefficient of kinetic friction between the ball and the table is µk.What should wo be(in terms of R,M,Vo,µk) so that the ball comes back with the same velocity, i.e. the velocity -Vo when rolling without slipping starts?
 
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I get w_o>4 Vo/R.
 
The time to get back to the original spot is T=2Vo/g*mu.
The angular acceleration of the ball is alpha=(3/2)g*mu/R.
This comes from R*g*mu=I*alpha, using the I for a hollow sphere.
Thus w=w_o-(3/2)g*mu*t/R=w_o-3 Vo/R.
and w must be greater than Vo/R.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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