- #1

MozAngeles

- 101

- 0

## Homework Statement

Find the area of the surface generated by these equations around the y axis

x=t

^{2}+1/(2t) y=4√t ; 1/√2≤t≤1

## Homework Equations

S=∫2[tex]\pi[/tex] x√(dx/dt)

^{2}+(dy/dt)

^{2})dt

## The Attempt at a Solution

dx/dt=2t-1/2t

^{2}squaring that, 4t

^{2-2/t+1/(4t4})

dy/dt=2/√t squaring that , 4/t

plugging this intot he formula

S= 2[tex]\pi[/tex]∫ (t

^{2}+1/(2t)√(4t

^{2}-2/t+1/(4t

^{4})+4/t)

S= 2[tex]\pi[/tex]∫ (t

^{2}+1/(2t) √((2t+1/(2t

^{2}))

^{2}

S= 2[tex]\pi[/tex]∫ (t

^{2}+1/(2t) (2t+1/(2t

^{2}))

so this is where I am stuck u sub almost works here, if it weren't for that pesky negative sign. So could someone help me maybe they noticed a mistake in my work. anything thank you much.