Find the average power of the crashed test car.

AI Thread Summary
In a crash test scenario, a car with a mass of 1734 kg traveling at 30.9 m/s comes to a stop in 0.8 seconds. To calculate the average power expended during the crash, the kinetic energy (KE) must be determined using the formula W = ΔKE, where the initial velocity is 30.9 m/s and the final velocity is 0 m/s. The power can then be calculated using P = W/t. The discussion highlights confusion regarding the correct application of equations and the determination of initial and final kinetic energy. Ultimately, the correct approach involves recognizing the initial velocity as 30.9 m/s and the final velocity as 0 m/s to find the average power.
pstrokeslibs
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Homework Statement



In a crash test, a test car of mass 1734 kg is moving at a speed of 30.9 m/s (= 69.5 miles per hour) when it crashes into a wall. If the car comes to rest in 0.8 s, how much average power (in W) is expended in this process?

Homework Equations



P=W/t to find "P"
W=Fd to find "W"
F=ma to find "F"
v=d/t to find "d"
a=v/t to find "a"

The Attempt at a Solution



i think the problem gives us, time(t)=0.8s, mass of car(m)=1734kg, velocity(v)=30.9m/s. i already did it by all of those equation, but the answer still wrong, or it's because of my equation that wrong.. sorry for my poor english, I am an Asian exchange student here in the US, please help me :(

thank you! :)
 
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Well the energy it has is kinetic energy, which is being used in the 0.8 seconds.

So use P = W/t and get the power.
 
So we can use equation W=(delta)KE right? but what is the initial KE and final KE... I am sorry

should the initial velocity be 30.9m/s and the final velocity 0m/s?? I am going to use W=1/2m(finalvelocity^2-initialvelocity^2)

Thanks for help :D
 
Last edited:
pstrokeslibs said:
So we can use equation W=(delta)KE right? but what is the initial KE and final KE... I am sorry

should the initial velocity be 30.9m/s and the final velocity 0m/s?? I am going to use W=1/2m(finalvelocity^2-initialvelocity^2)

Thanks for help :D

Yes that would be it.
 
i got it now! thanks very much! but... the 30.9 is final velocity...
 
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