Find the average value of the function f(x,y)=x^2+y^2

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Homework Statement


Let a>0 be a constant. Find the average value of the function f(x,y)=x^2+y^2
1) on the square -a\leqx\leqa, -a\leqy\leqa
2) on the disk x^2+y^2\leqa^2

Homework Equations





The Attempt at a Solution


1) I integrated \inta-(-a) \inta-(-a) (x^2+y^2) dxdy and got (8/3)a^4..Is this right?

2)I converted it to polar coordinates 0\leq\theta\leq2pi
and 0\leqr\leqsqrt(a)
i integrated \int0-2pi\int0-sqrt(a) r^2drd\theta
and got 2/3pi*(sqrt(a)^3)... is this right?----- 2pi\frac{\sqrt{a}^3}{3}
 
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For 1, I get (2/3)a^2 for the average value. Because of the symmetry of the region and the integrand, I took a short cut and integrated from 0 to a for both x and y, and multiplied the result by 4. Don't forget that for the average value, you have to divide by the area of the region, which is 4a^2. Your answer divided by 4a^2 equals mine.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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