- #1

Jaccobtw

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- Homework Statement
- An AC circuit contains a capacitor, an inductor, and two resistors of equal resistance as shown in the figure. The source provides 20V rms at 60Hz. When the switch is open as shown, the rms current is 183mA. When the switch is closed in position a, the rms current is 298mA. When the switch is closed in position b, the rms current is 137mA. What is the value of the capacitor in F?

- Relevant Equations
- $$X_C = \frac{1}{\omega C}$$

$$X_L = \omega L$$

$$ Z = \sqrt{R^{2} + (X_L - X_C)^{2}}$$

$$I_0 = \frac{V_0}{Z}$$

You can find the impedance for each of the three positions with V/I. However I'm not sure how to find the inductive and capacitive reactance. Thanks for your help.