f(x) = (x-1) 2/3
We were asked to find the derivative using the alternate limit form when c = 1 and then I was then I was trying to find the derivative using the multiplication rule (u dv + v du).
f'(u*v) = u dv + v du
f'(xn) = nxn-1
The Attempt at a Solution
When I did this, I got (2(x-1)-1/3)/3 which doesn't match the correct answer I got when I used the alternate limit form: 1/(x-1)^(2/3)
My question is if you can use the exponent rule on a polynomial and why it's not working out to be the same thing. Also, if you use the alternate limit form, does that mean it's the derivative for that c value only?