Find the determinant using row operations

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SUMMARY

The discussion centers on calculating the determinant of a 3x3 matrix using row operations. The matrix in question is: 1 -2 2; 0 5 -1; 2 -4 1. The user initially calculated the determinant as -30 after performing row operations, but the correct determinant is -15. The confusion arises from the distinction between adding a multiple of a row to another row, which does not change the determinant, and multiplying a row by a scalar, which does. The relevant theorem states that interchanging rows changes the sign of the determinant, multiplying a row by k multiplies the determinant by k, and adding a multiple of one row to another does not affect the determinant.

PREREQUISITES
  • Understanding of 3x3 matrices and their determinants
  • Familiarity with row operations in linear algebra
  • Knowledge of the properties of determinants
  • Basic linear algebra concepts, including matrix manipulation
NEXT STEPS
  • Study the properties of determinants in linear algebra textbooks
  • Practice calculating determinants using various row operations
  • Explore the theorem on determinants and row operations in detail
  • Utilize online matrix calculators to verify determinant calculations
USEFUL FOR

Students studying linear algebra, educators teaching matrix theory, and anyone looking to deepen their understanding of determinants and row operations.

vs55
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Homework Statement


find the determinant using row operations:
1 -2 2
0 5 -1
2 -4 1



Homework Equations





The Attempt at a Solution


i took row 3 and took 2 x row 1 away from it to get :
1 -2 2
0 5 -1
0 0 -3
1 x 5 x (-3) = -15...but i multiplied a row by 2 so i should get -30 for the det right?but the answer in my book is -15..what am i doing wrong?
 
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Calculating the determinant for A, a 3x3 matrix with elements:
a b c
d e f
g h i

Det(A) = a(ei - fh) - b(di - fg) + c(dh-eg), by starting with row 1.

So -15 is the answer you should be getting.
 


Adding a row or a multiple of a row to another row doesn't change the value of the determinant. If you had replaced a row by a multiple of itself, then the determinant's value would have changed.
 


hmmm well i looked over my book, and it said if i multiply a row by k...i multiply the determinant by k...so when do we multiply the determinant by k?..cause what i did was that not multiplying a row by k(2)?

and thanks for ur help guys
 


vs55 said:
hmmm well i looked over my book, and it said if i multiply a row by k...i multiply the determinant by k...so when do we multiply the determinant by k?..cause what i did was that not multiplying a row by k(2)?

and thanks for ur help guys
You did not replace a row by some multiple of itself; you added a multiple of a row to another row. These are different operations. On the other hand, if you had replaced row 1 by -2 times itself, and then added the first row to the third row, then your determinant would have been +30. This is not what you did though, since the first row stayed the same from start to finish.

In one of the linear algebra books I have, there is a theorem about determinants and row operations. The theorem has three parts.
  1. If you interchange two rows, the determinant of the new matrix will be -1 times the determinant of the old matrix.
  2. If you replace a row by k times itself, the determinant of the new matrix will be k times the determinant of the old matrix.
  3. If you add k times one row to another row, the determinant of the new matrix will be equal to the determinant of the old matrix.
 

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